Move regularity for the L so you can regularity within the mL so that the tools to possess thickness (grams mL -1 ) could well be consistent:

Move regularity for the L so you can regularity within the mL so that the tools to possess thickness (grams mL -1 ) could well be consistent:

(ii) Have you ever used the correct number of high numbers? thickness (1.03 ) have step 3 tall numbers regularity (1) provides 1 tall contour When multiplying otherwise separating, just how many extreme figures in the result is an equivalent given that minimum number of high data regarding the words utilized, therefore we are justified in using 1 significant profile. The address (ten30) enjoys cuatro tall numbers! As the our company is simply rationalized in using step one high contour, we are able to give the respond to since the one thousand grams, however the best solution is always to play with medical notation and you can produce step 1 ? ten 3 g

(iii) Is the address plausible? Would a “rough” calculation: thickness ≈ 1 g mL -step one step one mL out of dairy keeps scores of throughout the step 1 g step 1 L (a thousand mL) of dairy has actually scores of in the a lot of ? 1 = a lot of g Because this harsh formula is nearly brand new carefully computed worthy of getting size the audience is fairly positive that our address is right.

Question 5. At the 25°C and you may step 1 automatic teller machine tension, diamond has actually a density away from step 3.5 g cm -step 3 . Calculate the volume for the cm step 3 from 0.50 grams off diamond within 25°C and you will step one automatic teller machine stress.

step 3.5 g cm -3 ? V (cm step three ) = V(cm step 3 ) ? 0.fifty g ? V (cm 3 ) step three.5 g cm -3 korean chat room free? V (cm step three ) = 0.fifty grams

[ 3.5 g cm -step three ? V (cm step 3 )] ? step three.5 grams cm -3 = 0.50 g ? step three.5 grams cm -step 3 V (cm step 3 ) = 0.50 ? step three.5 (cm -3 ) = 0.14 cm step 3

Do good “rough” calculation: occurrence ≈ 5 grams cm -step three 1 cm -3 out of diamond has actually a mass of on 5 g

(ii) Have you utilized the proper quantity of extreme figures? occurrence (step 3.5) has dos significant data volume (0.50) provides 2 high numbers Whenever multiplying otherwise dividing, the number of tall rates on result is an identical since the very least level of significant data throughout the terms and conditions used, so we was warranted in using 2 tall figures. Our answer (0.14) possess dos high data

(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.

Question six. Within twenty-five°C and you can step one automatic teller machine tension, ethylene glycol have a thickness of just one.11 g mL -step one . Calculate the quantity for the mL off 0.025 kg regarding ethylene glycol on twenty-five°C and you can step one automatic teller machine pressure.

Transfer size within the kg to help you bulk within the grams so you can remain consistent with gadgets of thickness (grams mL -1 ):

V (mL) ? 1.eleven (grams mL -1 ) = V (mL) ? 25 (g) ? V (mL) V (mL) ? step 1.11 (g mL -step one ) = twenty five (g)

Practical question gives us 0

[V (mL) ? 1.eleven (grams mL -step one ) ] ? 1.eleven (g mL -1 ) = twenty-five (g) ? 1.11 ( g mL -step one ) V (mL) = twenty-five ? step 1.eleven (mL -step 1 ) = 23 mL

(ii) Maybe you’ve used the right quantity of extreme numbers? size (0.025) possess dos significant figures density (1.11) has step three high figures Whenever multiplying otherwise dividing, the number of extreme numbers on the outcome is a similar once the minimum number of high data throughout the conditions used, therefore we is justified in using 2 high numbers. All of our respond to (25) has dos tall numbers

Leave a Comment

Your email address will not be published. Required fields are marked *